Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

In the nuclear reaction $X(n, \alpha){}_{3}^{7}\mathrm{Li}$ , the term $X$ will be:

${}_{5}^{10}\mathrm{B}$

${}_{5}^{9}\mathrm{B}$

${}_{5}^{11}\mathrm{B}$

${}_{2}^{4}\mathrm{He}$

Interpret Reaction Notation: The notation $X(n, \alpha)Y$ represents a nuclear reaction where a target nucleus $X$ absorbs a neutron ( $n$ ) and emits an \alpha particle ( $\alpha$ ) to form the product nucleus $Y$ . The reaction is written as: $X + {}_{0}^{1}n \rightarrow {}_{3}^{7}\mathrm{Li} + {}_{2}^{4}\mathrm{He}$ .
Apply Conservation Laws: In any nuclear reaction, both the mass number ( $A$ , sum of protons and neutrons) and the atomic number ( $Z$ , number of protons) must be conserved .

Identify Element: The element with atomic number $Z=5$ is Boron (B). Therefore, the unknown term $X$ is the isotope Boron-10 ( ${}_{5}^{10}\mathrm{B}$ ).

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