Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

Identify the function which represents a non-periodic motion?

$e^{-\omega t}$

$\sin \omega t$

$\sin \omega t + \cos \omega t$

$\sin(\omega t + \pi/4)$

Definition of Periodic Motion: A function $f(t)$ represents periodic motion if it repeats its value at regular intervals of time, i.e., $f(t) = f(t + T)$ , where $T$ is the time period. Trigonometric functions like sine and cosine are fundamental periodic functions.
Analysis of Options: $\sin \omega t$ : This is a basic periodic function with period $T = 2\pi/\omega$ . $\sin \omega t + \cos \omega t$ : This represents the superposition of two periodic functions with the same frequency. It can be rewritten as $\sqrt{2}\sin(\omega t + \pi/4)$ , which is a Simple Harmonic Motion (a type of periodic motion) with period $T = 2\pi/\omega$ . $\sin(\omega t + \pi/4)$ : This is a sine function with a phase shift, which remains periodic with period $T = 2\pi/\omega$ . $e^{-\omega t}$ : This is an exponential function. It represents exponential decay where the value decreases continuously towards zero as time increases. It never repeats its value. Therefore, it represents non-periodic motion.
Conclusion: The function $e^{-\omega t}$ is the only non-periodic function among the options.

Practice Mode Available

Join thousands of students and practice with AI-generated mock tests.