Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

The figure given below shows the displacement and time, $(x-t)$ graph of a particle moving along a straight line: The correct statement, about the motion of the particle, is:

the particle moves at a constant velocity up to a time $t_0$ and then stops.

the particle is accelerated throughout its motion.

the particle is accelerated continuously for time $t_0$ then moves with constant velocity.

the particle is at rest.

Step-by-Step Solution

Interpret Slope: The slope of a displacement-time ( $x-t$ ) graph represents the velocity of the particle ( $v = \frac{dx}{dt}$ ) .
Analyze Phase 1 (0 to $t_0$ ): If the graph is a straight line inclined to the time axis (implied by the correct option describing 'constant velocity'), the slope is constant and non-zero. This indicates uniform motion (constant velocity).
Analyze Phase 2 (After $t_0$ ): If the particle 'stops', its velocity becomes zero. On an $x-t$ graph, zero velocity corresponds to a zero slope, which is a horizontal line parallel to the time axis. The position $x$ remains constant as time increases .
Conclusion: The graph describes a particle moving with uniform velocity until $t_0$ and then coming to rest.

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