Given: Velocity of sound, $v = 330 \text{ m/s}$ Wavelength of the first wave, $\lambda_1 = 5.0 \text{ m}$ Wavelength of the second wave, $\lambda_2 = 5.5 \text{ m}$

The frequencies of the two sound waves can be calculated using the relation $f = \frac{v}{\lambda}$: $f_1 = \frac{v}{\lambda_1} = \frac{330}{5.0} = 66 \text{ Hz}$ $f_2 = \frac{v}{\lambda_2} = \frac{330}{5.5} = 60 \text{ Hz}$

The number of beats produced per second is the difference between their frequencies: $\text{Number of beats} = f_1 - f_2 = 66 - 60 = 6$