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Three blocks with masses mm, 2m2m, and 3m3m are connected by strings as shown in the figure. After an upward force FF is applied on block mm, the masses move upward at constant speed vv. What is the net force on the block of mass 2m2m? (gg is the acceleration due to gravity)

A

2mg2mg

B

3mg3mg

C

6mg6mg

D

zero

Step-by-Step Solution

  1. Analyze Motion: The problem states that the system of blocks moves upward with a constant speed vv. Since the speed and direction are constant, the velocity is constant.
  2. Determine Acceleration: According to the definition of acceleration (a=dvdta = \frac{dv}{dt}), if velocity is constant, the acceleration is zero (a=0a = 0) [NCERT Class 11, Physics Part I, Laws of Motion, Sec 4.5].
  3. Apply Newton's Second Law: The net force acting on a body is given by the product of its mass and acceleration (Fnet=maF_{net} = ma).
  4. Calculate Net Force: For the block of mass 2m2m: Fnet=(2m)×0=0F_{net} = (2m) \times 0 = 0 The block is in dynamic equilibrium. This means the vector sum of all forces acting on it (tension from the upper string, tension from the lower string, and its own weight) is zero [NCERT Class 11, Physics Part I, Laws of Motion, Sec 4.8 Equilibrium of a Particle].
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