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NEET PHYSICSMedium

If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is

A

1:11:1

B

2:1\sqrt{2}:1

C

1:21:\sqrt{2}

D

1:21:2

Step-by-Step Solution

We know, velocity of transverse wave v=Tμv = \sqrt{\frac{T}{\mu}}. Let initial tension be TT and final tension be 2T2T. Then vi=Tμv_i = \sqrt{\frac{T}{\mu}} and vf=2Tμv_f = \sqrt{\frac{2T}{\mu}}. Therefore, vivf=12\frac{v_i}{v_f} = \frac{1}{\sqrt{2}}.

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