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NEET PHYSICSEasy

The dependence of acceleration due to gravity g on the distance r from the centre of the earth assumed to be a sphere of radius R of uniform density is as shown in the figure below:

A

Graph showing linear increase up to R, then curvilinear decrease

B

Graph showing constant g up to R, then decrease

C

Graph showing curvilinear increase

D

Graph showing linear decrease

Step-by-Step Solution

The acceleration due to gravity (gg) varies with the distance (rr) from the centre of the Earth as follows:

  1. Inside the Earth (r<Rr < R): Assuming the Earth to be a sphere of uniform density, gg is directly proportional to the distance from the centre. The formula is g=GMR3rg = \frac{GM}{R^3}r, which implies grg \propto r. This relationship is represented by a straight line passing through the origin and increasing up to the surface.
  2. At the Surface (r=Rr = R): The value of gg is maximum, g=GMR2g = \frac{GM}{R^2}.
  3. Outside the Earth (r>Rr > R): The value of gg decreases as the distance increases, following the inverse square law. The formula is g=GMr2g = \frac{GM}{r^2}, which implies g1r2g \propto \frac{1}{r^2}. This is represented by a curve (hyperbola) decreasing asymptotically towards zero.

Therefore, the correct graph shows a linear increase for r<Rr < R and a curvilinear decrease for r>Rr > R.

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