Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A stone dropped from the top of the tower touches the ground in $4 \text{ sec}$ . The height of the tower is about:

80 m

40 m

20 m

160 m

Analyze Initial Conditions: The stone is dropped, implying an initial velocity $u = 0$ . The time taken to reach the ground is $t = 4 \text{ s}$ . Acceleration due to gravity $a = g$ . To estimate 'about' the height, we can approximate $g \approx 10 \text{ m/s}^2$ (or use $9.8 \text{ m/s}^2$ ).
Apply Kinematic Equation: Use the equation for displacement in uniformly accelerated motion: $h = ut + \frac{1}{2}gt^2$ .
Calculation: $h = (0)(4) + \frac{1}{2}(10)(4)^2$ $h = 0 + 5(16) = 80 \text{ m}$ . (Note: Using precise $g=9.8 \text{ m/s}^2$ , $h = 0.5(9.8)(16) = 78.4 \text{ m}$ , which rounds to $80 \text{ m}$ ).

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