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NEET PHYSICSEasy

Dimensional formula of magnetic flux is:

A

ML2T2A1ML^2T^{-2}A^{-1}

B

ML0T2A2ML^0T^{-2}A^{-2}

C

M0L2T2A3M^0L^{-2}T^{-2}A^{-3}

D

ML2T2A3ML^2T^{-2}A^3

Step-by-Step Solution

Magnetic flux (ΦB\Phi_B) is defined as the scalar product of the magnetic field (B\mathbf{B}) and the area vector (A\mathbf{A}), expressed as ΦB=BAcosθ\Phi_B = BA \cos \theta . Area has the dimensions [L2][L^2] . The dimensions for the magnetic field (BB) can be derived from the Lorentz force formula, F=qvBsinθF = qvB \sin \theta, which gives B=F/(qv)B = F/(qv) . Since Force (FF) has dimensions [MLT2][MLT^{-2}] , charge (qq) is [AT][AT] , and velocity (vv) is [LT1][LT^{-1}] , the dimensions for BB are [MT2A1][MT^{-2}A^{-1}] . Consequently, the dimensional formula for magnetic flux is calculated by multiplying these: [MT2A1]×[L2]=[ML2T2A1][MT^{-2}A^{-1}] \times [L^2] = [ML^2T^{-2}A^{-1}] .

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