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NEET PHYSICSEasy

In a certain region of space, the electric field is along the z-direction throughout. The magnitude of the electric field is, however, not constant but increases uniformly along the positive z-direction, at the rate of 10510^5 NC1^{-1} per meter. What is the torque experienced by a system having a total dipole moment equal to 10710^{-7} C-m in the negative z-direction?

A

10210^{-2} N-m

B

0

C

10110^{-1} N-m

D

0.01 N-m

Step-by-Step Solution

The torque τ\vec{\tau} experienced by an electric dipole is given by the cross product τ=p×E\vec{\tau} = \vec{p} \times \vec{E}, with magnitude τ=pEsinθ\tau = pE \sin\theta. Here, the electric field E\vec{E} is along the positive z-direction, and the dipole moment p\vec{p} is along the negative z-direction. The angle θ\theta between them is 180180^\circ. Since sin(180)=0\sin(180^\circ) = 0, the torque is zero. Note: The non-uniformity of the field (dE/dzdE/dz) results in a net force on the dipole (F=pdEdzF = p \frac{dE}{dz}), but the torque remains zero because the forces on the charges act along the same line. (See NCERT Physics Class 12, Exercise 1.27).

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