Back to Directory
NEET PHYSICSEasy

The nuclei 613C_{6}^{13}\text{C} and 714N_{7}^{14}\text{N} can be described as:

A

isotones

B

isobars

C

isotopes of carbon

D

isotopes of nitrogen

Step-by-Step Solution

  1. Formula: The number of neutrons (nn) in a nucleus is found by subtracting the atomic number (ZZ) from the mass number (AA): n=AZn = A - Z .
  2. Calculation for Carbon-13 (613C_{6}^{13}\text{C}):
  • Mass Number (AA) = 13
  • Atomic Number (ZZ) = 6
  • Neutrons = 136=713 - 6 = 7
  1. Calculation for Nitrogen-14 (714N_{7}^{14}\text{N}):
  • Mass Number (AA) = 14
  • Atomic Number (ZZ) = 7
  • Neutrons = 147=714 - 7 = 7
  1. Conclusion: Species with different atomic numbers but the same number of neutrons are called isotones. Since both nuclei contain exactly 7 neutrons, they are isotones. (Note: Isotopes have the same ZZ, Isobars have the same AA) .
Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started