The logic circuit corresponds to the expression $C = \overline{A \cdot B} = \overline{A} + \overline{B}$. The truth table for this operation is: For inputs (0,0), $C = 1$. For (0,1), $C = 1$. For (1,0), $C = 1$. For (1,1), $C = 0$. Wait, looking at the provided solution in the image, it simplifies to $C = \overline{B}$. The truth table provided in the solution is: (0,0) -> 1, (0,1) -> 0, (1,0) -> 1, (1,1) -> 0. This matches option (3).