According to the average form of Newton's law of cooling:
tT1−T2=K(2T1+T2−Ts)
where Ts is the temperature of the surroundings.
For the first 5 minutes:
570−60=K(270+60−Ts)
2=K(65−Ts) ... (i)
For the next 5 minutes:
560−54=K(260+54−Ts)
1.2=K(57−Ts) ... (ii)
Dividing equation (i) by (ii):
1.22=57−Ts65−Ts
35=57−Ts65−Ts
5(57−Ts)=3(65−Ts)
285−5Ts=195−3Ts
2Ts=90
Ts=45∘C
Therefore, the temperature of the surroundings is 45∘C.