Solved: PHYSICS Question for NEET

NEET PHYSICSHard

Light travels a distance $x$ in time $t_1$ in air and $10x$ in time $t_2$ in another denser medium. What is the critical angle for this medium?

$\sin^{-1}\left(\frac{t_2}{t_1}\right)$

$\sin^{-1}\left(\frac{10t_2}{t_1}\right)$

$\sin^{-1}\left(\frac{t_1}{10t_2}\right)$

$\sin^{-1}\left(\frac{10t_1}{t_2}\right)$

Step-by-Step Solution

Speed in air $v_1 = \frac{x}{t_1} = c$ . Speed in medium $v_2 = \frac{10x}{t_2}$ . Refractive index $\mu = \frac{v_1}{v_2} = \frac{x/t_1}{10x/t_2} = \frac{t_2}{10t_1}$ . Critical angle $C = \sin^{-1}\left(\frac{1}{\mu}\right) = \sin^{-1}\left(\frac{10t_1}{t_2}\right)$ .

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