Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms⁻¹ to 20 ms⁻¹ while passing through a distance of 135 m in t seconds. The value of t is:

1.8

Step-by-Step Solution

Identify Given Values: Initial velocity ( $v_0$ or $u$ ) = 10 ms⁻¹ Final velocity ( $v$ ) = 20 ms⁻¹ Displacement ( $x$ or $s$ ) = 135 m Time interval = $t$
Select Kinematic Equation: For uniformly accelerated motion, the displacement is equal to the average velocity multiplied by the time interval: $x = \left( \frac{v + v_0}{2} \right) t$
Calculation: Substitute the known values into the equation: $135 = \left( \frac{20 + 10}{2} \right) t$ $135 = \left( \frac{30}{2} \right) t$ $135 = 15t$ $t = \frac{135}{15} = 9 \text{ s}$

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