According to Gauss's Law, the net electric flux $\Phi_E$ through a closed surface is equal to the net charge $q$ enclosed divided by the permittivity of free space $\varepsilon_0$ ($\Phi_E = q/\varepsilon_0$). Given: $\Phi_E = 8.0 \times 10^3$ Nm$^2$/C $\varepsilon_0 \approx 8.854 \times 10^{-12}$ C$^2$/Nm$^2$

Calculation: $q = \Phi_E \times \varepsilon_0$ $q = (8.0 \times 10^3) \times (8.854 \times 10^{-12})$ $q = 70.832 \times 10^{-9}$ C $q \approx 0.07 \times 10^{-6}$ C $= 0.07$ \mu C. (See NCERT Physics Class 12, Exercise 1.16).