According to Kepler's Second Law of planetary motion (Law of Areas), the line joining the Sun and the planet sweeps out equal areas in equal intervals of time. This implies that the areal velocity is constant ($\frac{dA}{dt} = \text{constant}$), meaning the area swept ($A$) is directly proportional to the time taken ($t$). Mathematically, $\frac{A_1}{t_1} = \frac{A_2}{t_2}$. Given that the Area SCD ($A_1$) is twice the Area SAB ($A_2$), i.e., $A_1 = 2A_2$, we have: $\frac{2A_2}{t_1} = \frac{A_2}{t_2}$ $\Rightarrow t_1 = 2t_2$.