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NEET PHYSICSEasy

Which one of the following plots represent the variation of gravitational field on a particle at distance rr, due to a thin spherical shell of radius RR? (rr is measured from the centre of the spherical shell).

A

Option 1

B

Option 2

C

Option 3

D

Option 4

Step-by-Step Solution

  1. Gravitational Field Inside a Shell (r<Rr < R): According to Newton's shell theorem, the force of attraction (and thus the gravitational field EE or gg) on a point mass situated inside a thin spherical shell of uniform density is zero at all points. Thus, for 0r<R0 \le r < R, E=0E = 0.
  2. Gravitational Field Outside a Shell (rRr \ge R): For a point situated outside the shell, the gravitational force is the same as if the entire mass MM of the shell were concentrated at its centre. Thus, the field follows the inverse square law: E=GMr2E = \frac{GM}{r^2}.
  3. At the Surface (r=Rr = R): The field is maximum, E=GMR2E = \frac{GM}{R^2}.
  4. Graphical Representation: The correct plot must show E=0E=0 for r<Rr < R. At r=Rr=R, the graph jumps discontinuously to a maximum value and then decreases as 1/r21/r^2 for r>Rr > R. This specific shape (zero then a sharp rise followed by a hyperbolic decay) corresponds to Option 2 in the standard set of graphs for this problem.
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