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NEET PHYSICSMedium

Find the value of the angle of emergence from the prism. Refractive index of the glass is 3\sqrt{3}.

1

60∘60^\circ

2

30∘30^\circ

3

45∘45^\circ

4

90∘90^\circ

Step-by-Step Solution

From the ray diagram, at point P, using Snell's law: sin⁡isin⁡r=μairμprism\frac{\sin i}{\sin r} = \frac{\mu_{air}}{\mu_{prism}}. Here i=30∘i = 30^\circ and μprism=3\mu_{prism} = \sqrt{3}. So sin⁡30∘sin⁡e=13\frac{\sin 30^\circ}{\sin e} = \frac{1}{\sqrt{3}}. sin⁡e=3⋅sin⁡30∘=3⋅12=32\sin e = \sqrt{3} \cdot \sin 30^\circ = \sqrt{3} \cdot \frac{1}{2} = \frac{\sqrt{3}}{2}. Therefore, e=60∘e = 60^\circ.

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