Identify the Neutral Point: The gravitational field is zero at a point where the forces due to the two masses cancel each other out. Let this point be at a distance $x$ from mass $m$. Consequently, it is at a distance $(R-x)$ from mass $9m$. $\frac{Gm}{x^2} = \frac{G(9m)}{(R-x)^2}$ Taking the square root of both sides: $\frac{1}{x} = \frac{3}{R-x} \Rightarrow R - x = 3x \Rightarrow 4x = R \Rightarrow x = \frac{R}{4}$ The distance from $9m$ is $R - \frac{R}{4} = \frac{3R}{4}$.

Calculate Gravitational Potential: The total gravitational potential $V$ is the scalar sum of the potentials due to each mass at that point ($V = -\frac{GM}{r}$). $V = -\frac{Gm}{x} - \frac{G(9m)}{R-x}$ Substitute the distances: $V = -\frac{Gm}{R/4} - \frac{9Gm}{3R/4}$ $V = -\frac{4Gm}{R} - \frac{36Gm}{3R}$ $V = -\frac{4Gm}{R} - \frac{12Gm}{R} = -\frac{16Gm}{R}$