Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A particle starts its motion from rest under the action of a constant force. If the distance covered in the first 10 s is S₁ and that covered in the first 20 s is S₂, then:

S₂ = 2S₁

S₂ = 3S₁

S₂ = 4S₁

S₂ = S₁

Step-by-Step Solution

Identify Conditions: The particle starts from rest ( $u = 0$ ) under a constant force, which implies constant acceleration ( $a$ ) according to Newton's Second Law ( $F=ma$ ) .
Select Kinematic Equation: For a particle moving with constant acceleration starting from rest, the distance ( $S$ ) covered in time ( $t$ ) is given by the equation: $S = ut + \frac{1}{2}at^2$ Since $u=0$ , this simplifies to: $S = \frac{1}{2}at^2$ Thus, distance is directly proportional to the square of time ( $S \propto t^2$ ) .
Calculate Distances: Distance covered in the first 10 seconds ( $t_1 = 10$ s): $S_1 = \frac{1}{2}a(10)^2 = 50a$ Distance covered in the first 20 seconds ( $t_2 = 20$ s): $S_2 = \frac{1}{2}a(20)^2 = 200a$
Determine Relationship: Taking the ratio of $S_2$ to $S_1$ : $\frac{S_2}{S_1} = \frac{200a}{50a} = 4$ $S_2 = 4S_1$

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