Solved: PHYSICS Question for NEET | Sushrut

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NEET PHYSICSEasy

A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 ms⁻², the velocity with which it hits the ground is:

A

20 m/s

B

40 m/s

C

5 m/s

D

10 m/s

Step-by-Step Solution

Identify Given Values: Initial velocity ( $v_0$ ) = 0 (dropped from rest). Displacement ( $y$ ) = 20 m (taking downward direction as positive).

Acceleration ( $a$ ) = $g$ = 10 m/s².

Select Kinematic Equation: Use the equation connecting velocity, displacement, and acceleration: $v^2 = v_0^2 + 2ay$
Calculation: $v^2 = 0^2 + 2(10)(20)$ $v^2 = 400$ $v = \sqrt{400} = 20 \text{ m/s}$

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Solved: PHYSICS Question for NEET | Sushrut