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NEET PHYSICSEasy

Three capacitors each of capacitance CC and of breakdown voltage VV are joined in series. The capacitance and breakdown voltage of the combination will be:

A

C3,V3\frac{C}{3}, \frac{V}{3}

B

3C,V33C, \frac{V}{3}

C

C3,3V\frac{C}{3}, 3V

D

3C,3V3C, 3V

Step-by-Step Solution

  1. Equivalent Capacitance: For capacitors connected in series, the reciprocal of the equivalent capacitance (CeqC_{eq}) is the sum of the reciprocals of the individual capacitances [NCERT Class 12, Sec 2.14.1, Eq. 2.45]. 1Ceq=1C+1C+1C=3C\frac{1}{C_{eq}} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} = \frac{3}{C} Ceq=C3C_{eq} = \frac{C}{3}

  2. Breakdown Voltage: In a series combination, the total potential difference (voltage) is the sum of the potential differences across each capacitor (Vtotal=V1+V2+V3V_{total} = V_1 + V_2 + V_3). Since the capacitors are identical, the voltage distributes equally. If each capacitor can withstand a maximum voltage VV before breaking down, the combination can withstand a total voltage of V+V+V=3VV + V + V = 3V.

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