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NEET PHYSICSEasy

The ratio of the amplitude of the magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:

A

the speed of light in vacuum

B

reciprocal of speed of light in vacuum

C

the ratio of magnetic permeability to the electric susceptibility of vacuum

D

unity

Step-by-Step Solution

For an electromagnetic wave propagating in a vacuum, the relationship between the amplitude of the electric field (E0E_0) and the amplitude of the magnetic field (B0B_0) is given by the speed of light (cc): c=E0B0c = \frac{E_0}{B_0}

The question asks for the ratio of the amplitude of the magnetic field to the amplitude of the electric field (B0E0\frac{B_0}{E_0}). Rearranging the formula: B0E0=1c\frac{B_0}{E_0} = \frac{1}{c} Thus, the ratio is equal to the reciprocal of the speed of light in vacuum.

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Solved: PHYSICS Question for NEET | Sushrut