To find the RMS current ($I_{rms}$), we first calculate the capacitive reactance ($X_C$) using the formula $X_C = \frac{1}{2\pi fC}$. Given $C = 40 \times 10^{-6}\text{ F}$ and $f = 50\text{ Hz}$, $X_C = \frac{1}{2 \times 3.14 \times 50 \times 40 \times 10^{-6}} \approx 79.6 \ \Omega$. According to the sources, the RMS current is given by $I_{rms} = \frac{V_{rms}}{X_C}$ . Substituting the given RMS voltage ($200\text{ V}$), we get $I_{rms} = \frac{200}{79.6} \approx 2.51\text{ A}$. Therefore, the RMS current is nearly 2.5 A.