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The capacitance of a parallel plate capacitor with air as medium is 6μF6 \mu F. With the introduction of a dielectric medium, the capacitance becomes 30μF30 \mu F. The permittivity of the medium is : (ϵ0=8.85×10−12C2N−1m−2\epsilon_0 = 8.85 \times 10^{-12} C^2 N^{-1} m^{-2})

1

0.44×10−13C2N−1m−20.44 \times 10^{-13} C^2 N^{-1} m^{-2}

2

1.77×10−12C2N−1m−21.77 \times 10^{-12} C^2 N^{-1} m^{-2}

3

0.44×10−10C2N−1m−20.44 \times 10^{-10} C^2 N^{-1} m^{-2}

4

5.00C2N−1m−25.00 C^2 N^{-1} m^{-2}

Step-by-Step Solution

C=KC0C = KC_0. K=CC0=306=5K = \frac{C}{C_0} = \frac{30}{6} = 5. K=ϵϵ0K = \frac{\epsilon}{\epsilon_0}. ϵ=Kϵ0=5×8.85×10−12=0.44×10−10C2N−1m−2\epsilon = K\epsilon_0 = 5 \times 8.85 \times 10^{-12} = 0.44 \times 10^{-10} C^2 N^{-1} m^{-2}

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