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NEET PHYSICSMedium

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of CP/CVC_P/C_V for the gas is equal to:

A

4/34/3

B

22

C

5/35/3

D

3/23/2

Step-by-Step Solution

For an adiabatic process, the relation between pressure (PP) and temperature (TT) is given by P1γTγ=constantP^{1-\gamma}T^\gamma = \text{constant}, which can be rewritten as PTγγ1P \propto T^{\frac{\gamma}{\gamma-1}}. Given that PT3P \propto T^3. Equating the powers of TT, we get: γγ1=3\frac{\gamma}{\gamma - 1} = 3 γ=3γ3\gamma = 3\gamma - 3 2γ=3    γ=322\gamma = 3 \implies \gamma = \frac{3}{2} Since the ratio of specific heats CPCV=γ\frac{C_P}{C_V} = \gamma, the value is 32\frac{3}{2}.

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