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A person of mass 60 kg60 \text{ kg} is inside a lift of mass 940 kg940 \text{ kg} and presses the button on control panel. The lift starts moving upwards with an acceleration 1.0 m/s21.0 \text{ m/s}^2. If g=10 m/s2g=10 \text{ m/s}^2, the tension in the supporting cable is:

A

9680 N

B

11000 N

C

1200 N

D

8600 N

Step-by-Step Solution

  1. System Definition: The tension in the supporting cable pulls the entire system upwards. Therefore, we must consider the total mass of the system.
  • Mass of person, m=60 kgm = 60 \text{ kg}.
  • Mass of lift, M=940 kgM = 940 \text{ kg}.
  • Total Mass, Mtotal=M+m=940+60=1000 kgM_{total} = M + m = 940 + 60 = 1000 \text{ kg}.
  1. Forces Analysis:
  • Upward force: Tension (TT).
  • Downward force: Total Weight (W=MtotalgW = M_{total}g).
  • Net Acceleration: a=1.0 m/s2a = 1.0 \text{ m/s}^2 (upwards).
  1. Equation of Motion: Applying Newton's Second Law (Fnet=maF_{net} = ma) in the upward direction: TMtotalg=MtotalaT - M_{total}g = M_{total}a T=Mtotal(g+a)T = M_{total}(g + a) (Reference: NCERT Class 11, Physics Part I, Chapter 5, Laws of Motion, Section 5.9 Common Forces in Mechanics - similar logic applied to elevator problems).
  2. Calculation: Substitute the values (g=10 m/s2,a=1.0 m/s2g = 10 \text{ m/s}^2, a = 1.0 \text{ m/s}^2): T=1000 kg×(10+1) m/s2T = 1000 \text{ kg} \times (10 + 1) \text{ m/s}^2 T=1000×11T = 1000 \times 11 T=11000 NT = 11000 \text{ N}
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