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NEET PHYSICSEasy

The angle between the electric lines of force and the equipotential surface is:

A

180°

B

C

45°

D

90°

Step-by-Step Solution

  1. Definition: An equipotential surface is a region where the electric potential (VV) is constant at every point. Therefore, the potential difference (dVdV) between any two points on the surface is zero.
  2. Work Done: The work done to move a charge qq on an equipotential surface is dW=qdV=0dW = q dV = 0.
  3. Relation to Field: Work is also defined as the dot product of force and displacement: dW=Fdr=qEdr=qEdrcosθdW = \mathbf{F} \cdot d\mathbf{r} = q \mathbf{E} \cdot d\mathbf{r} = q E dr \cos \theta, where θ\theta is the angle between the electric field (E\mathbf{E}) and the displacement (drd\mathbf{r}) along the surface.
  4. Conclusion: For dWdW to be zero (where q,E,dr0q, E, dr \neq 0), cosθ\cos \theta must be zero. This implies θ=90\theta = 90^\circ. Thus, electric field lines are always perpendicular to equipotential surfaces.
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