Solved: PHYSICS Question for NEET | Sushrut

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NEET PHYSICSEasy

If a body is thrown up with the velocity of $15 \text{ m/s}$ , then the maximum height attained by the body is: (assume $g = 10 \text{ m/s}^2$ )

A

11.25 m

B

16.2 m

C

24.5 m

D

7.62 m

Step-by-Step Solution

Identify Given Values:

Initial velocity, $u = 15 \text{ m/s}$ .
Acceleration due to gravity, $g = 10 \text{ m/s}^2$ (acting downwards, so $a = -g$ ).
Final velocity at maximum height, $v = 0$ .

Select Kinematic Equation: Use the equation that relates velocity, acceleration, and displacement: $v^2 = u^2 + 2as$ Here, displacement $s = H$ (maximum height) .
Substitute and Solve: $0^2 = (15)^2 + 2(-10)H$ $0 = 225 - 20H$ $20H = 225$ $H = \frac{225}{20} = 11.25 \text{ m}$ .

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Solved: PHYSICS Question for NEET | Sushrut