Back to Directory
NEET PHYSICSMedium

A bullet is fired from a gun at the speed of 280 m s−1280 \text{ m s}^{-1} in the direction 30∘30^\circ above the horizontal. The maximum height attained by the bullet is (g=9.8 m s−2g = 9.8 \text{ m s}^{-2}, sin⁡30∘=0.5\sin 30^\circ = 0.5)

A

2800 m2800 \text{ m}

B

2000 m2000 \text{ m}

C

1000 m1000 \text{ m}

D

3000 m3000 \text{ m}

Step-by-Step Solution

The maximum height HH is given by H=u2sin⁡2θ2gH = \frac{u^2 \sin^2 \theta}{2g}. Substituting the values: H=(280)2×(sin⁡30∘)22×9.8=78400×0.2519.6=1960019.6=1000 mH = \frac{(280)^2 \times (\sin 30^\circ)^2}{2 \times 9.8} = \frac{78400 \times 0.25}{19.6} = \frac{19600}{19.6} = 1000 \text{ m}.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started