For an adiabatic process, the relation between pressure and temperature is given by $P^{1-\gamma}T^\gamma = \text{constant}$, which can be rearranged as $\frac{P_2}{P_1} = \left(\frac{T_2}{T_1}\right)^{\frac{\gamma}{\gamma-1}}$. Given: $P_1 = 2\text{ atm}$ $T_1 = 27^\circ\text{C} = 27 + 273 = 300\text{ K}$ $T_2 = 927^\circ\text{C} = 927 + 273 = 1200\text{ K}$ $\gamma = 1.4 = \frac{7}{5}$ Therefore, the power becomes $\frac{\gamma}{\gamma-1} = \frac{1.4}{0.4} = \frac{7}{2}$. Substituting the values into the relation: $P_2 = P_1 \times \left(\frac{T_2}{T_1}\right)^{\frac{\gamma}{\gamma-1}} = 2 \times \left(\frac{1200}{300}\right)^{\frac{7}{2}} = 2 \times (4)^{\frac{7}{2}} = 2 \times (2^2)^{\frac{7}{2}} = 2 \times 2^7 = 2 \times 128 = 256\text{ atm}$. Thus, the final pressure of the gas is $256\text{ atm}$.