Solved: Physics Question for NEET

NEET PhysicsMedium

Two bodies of mass $4\text{ kg}$ and $6\text{ kg}$ are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is :

g/2

g/5

g/10

Step-by-Step Solution

The acceleration of an Atwood machine is given by $a = \frac{(m_2 - m_1)g}{m_1 + m_2}$ where $m_2 > m_1$ . Here $m_2 = 6\text{ kg}$ and $m_1 = 4\text{ kg}$ . So, $a = \frac{(6 - 4)g}{6 + 4} = \frac{2g}{10} = \frac{g}{5}$ .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started