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NEET PHYSICSMedium

Ionized hydrogen atoms and α\alpha-particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths rH:rαr_H : r_\alpha will be :

A

2 : 1

B

1 : 2

C

4 : 1

D

1 : 4

Step-by-Step Solution

The radius of the path is r=pqBr = \frac{p}{qB}. For hydrogen, qH=eq_H = e. For α\alpha-particle, qα=2eq_\alpha = 2e. Thus, rHrα=p/eBp/2eB=21\frac{r_H}{r_\alpha} = \frac{p/eB}{p/2eB} = \frac{2}{1}.

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