Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A stone is thrown vertically downwards with an initial velocity of $40 \text{ m/s}$ from the top of a building. If it reaches the ground with a velocity of $60 \text{ m/s}$ , then the height of the building is: (take $g=10 \text{ m/s}^2$ )

120 m

140 m

80 m

100 m

Step-by-Step Solution

Identify Variables: Initial velocity ( $u$ ) = $40 \text{ m/s}$ (downwards) Final velocity ( $v$ ) = $60 \text{ m/s}$ (downwards) Acceleration ( $a$ ) = $g = 10 \text{ m/s}^2$ (acting downwards) Displacement ( $s$ ) = $h$ (height of the building)
Select Kinematic Equation: Use the third equation of motion which relates velocities and displacement : $v^2 - u^2 = 2as$
Substitute Values: $(60)^2 - (40)^2 = 2(10)h$ $3600 - 1600 = 20h$ $2000 = 20h$
Solve for Height ( $h$ ): $h = \frac{2000}{20} = 100 \text{ m}$

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