Back to Directory
NEET PHYSICSMedium

An electric dipole is placed at an angle of 30∘30^\circ with an electric field of intensity 2×1052 \times 10^5 N C−1^{-1}. It experiences a torque equal to 4 N m. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

A

8 mC

B

6 mC

C

4 mC

D

2 mC

Step-by-Step Solution

Torque τ=pEsin⁡θ\tau = pE \sin\theta, where p=q×(2a)p = q \times (2a). Given τ=4\tau = 4 N m, E=2×105E = 2 \times 10^5 N C−1^{-1}, θ=30∘\theta = 30^\circ, 2a=22a = 2 cm = 0.020.02 m. 4=q×0.02×2×105×sin⁡(30∘)4 = q \times 0.02 \times 2 \times 10^5 \times \sin(30^\circ). 4=q×0.02×2×105×0.54 = q \times 0.02 \times 2 \times 10^5 \times 0.5. 4=q×20004 = q \times 2000. q=4/2000=0.002q = 4 / 2000 = 0.002 C = 2 mC.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut