Back to Directory
NEET PhysicsMedium

Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m with negligible mass. The centre of mass of the system from the 5 kg particle is nearly at a distance of :

1

33 cm

2

50 cm

3

67 cm

4

80 cm

Step-by-Step Solution

Using the center of mass formula xcm=m1x1+m2x2m1+m2x_{cm} = \frac{m_1x_1 + m_2x_2}{m_1 + m_2}. With m1=5,x1=0m_1=5, x_1=0 and m2=10,x2=100 cmm_2=10, x_2=100 \text{ cm}, we get xcm=5(0)+10(100)5+10=100015=66.66 cm≈67 cmx_{cm} = \frac{5(0) + 10(100)}{5+10} = \frac{1000}{15} = 66.66 \text{ cm} \approx 67 \text{ cm}.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: Physics Question for NEET | Sushrut