Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A man of mass 80 kg is standing in an elevator which is moving with an acceleration of 6 m/s² in the upward direction. The apparent weight of the man will be (g = 10 m/s²):

1480 N

1280 N

1380 N

None of these

Step-by-Step Solution

Identify the Forces: The forces acting on the man are:

Weight ( $mg$ ): Acting vertically downwards. $W = 80 \text{ kg} \times 10 \text{ m/s}^2 = 800 \text{ N}$ .
Normal Reaction ( $N$ ): The force exerted by the floor acting vertically upwards. This is the apparent weight.

Apply Newton's Second Law: The elevator and the man are accelerating upwards with acceleration $a = 6 \text{ m/s}^2$ . The net force $F_{net}$ is in the direction of acceleration (upwards). $F_{net} = N - mg = ma$
Solve for Apparent Weight ( $N$ ): $N = m(g + a)$ $N = 80 \text{ kg} \times (10 \text{ m/s}^2 + 6 \text{ m/s}^2)$ $N = 80 \times 16$ $N = 1280 \text{ N}$ [Source 75]

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