Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

If a car at rest accelerates uniformly to a speed of $144 \text{ km/h}$ in $20 \text{ s}$ , then it covers a distance of:

20 m

400 m

1440 m

2880 m

Convert Units: First, convert the final speed from km/h to m/s. $v = 144 \text{ km/h} = 144 \times \frac{5}{18} \text{ m/s} = 40 \text{ m/s}$ .
Identify Given Values: Initial velocity, $u = 0$ (at rest). Final velocity, $v = 40 \text{ m/s}$ .

Select Formula: For uniform acceleration, the distance $s$ can be calculated using the average velocity formula: $s = \left(\frac{u + v}{2}\right)t$ . Alternatively, use $v = u + at$ to find acceleration and then $s = ut + \frac{1}{2}at^2$ .
Calculation (Method 1): $s = \left(\frac{0 + 40}{2}\right) \times 20$ $s = 20 \times 20 = 400 \text{ m}$ .
Calculation (Method 2): $a = \frac{v - u}{t} = \frac{40 - 0}{20} = 2 \text{ m/s}^2$ . $s = 0(20) + \frac{1}{2}(2)(20)^2 = 400 \text{ m}$ .

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