The energy that will be ideally radiated by a 100 kW100\text{ kW}100 kW transmitter in 1 hour1\text{ hour}1 hour is
36×107 J36 \times 10^7\text{ J}36×107 J
36×104 J36 \times 10^4\text{ J}36×104 J
36×105 J36 \times 10^5\text{ J}36×105 J
1×105 J1 \times 10^5\text{ J}1×105 J
Energy = Power ×\times× time. E=100×103×3600=36×107 JE = 100 \times 10^3 \times 3600 = 36 \times 10^7\text{ J}E=100×103×3600=36×107 J.
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