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NEET PHYSICSEasy

In S = a + bt + ct², S is measured in metres and t in seconds. The unit of c will be:

A

none

B

m

C

ms⁻¹

D

ms⁻²

Step-by-Step Solution

According to the Principle of Homogeneity of dimensions, the magnitudes of physical quantities may be added together or subtracted from one another only if they have the same dimensions .

  1. In the given equation S=a+bt+ct2S = a + bt + ct^2, the quantity SS represents a length (measured in metres).
  2. Therefore, each term on the right-hand side (aa, btbt, and ct2ct^2) must also have the dimensions of length [L][L] and the unit of metres (mm).
  3. For the term ct2ct^2: Unit of (ct2)=Unit of S\text{Unit of } (ct^2) = \text{Unit of } S (Unit of c)×(Unit of t)2=m(\text{Unit of } c) \times (\text{Unit of } t)^2 = m (Unit of c)×s2=m(\text{Unit of } c) \times s^2 = m Unit of c=m/s2=ms2\text{Unit of } c = m/s^2 = ms^{-2}

This is consistent with the standard kinematic equation x=x0+v0t+12at2x = x_0 + v_0t + \frac{1}{2}at^2, where the coefficient of t2t^2 involves acceleration (aa) with units ms2ms^{-2}.

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