Back to Directory
NEET PHYSICSEasy

The magnetic field in a plane electromagnetic wave is given by: By=2×107sin(π×103x+3π×1011t) TB_y = 2 \times 10^{-7} \sin(\pi \times 10^3x + 3\pi \times 10^{11}t) \text{ T}. The wavelength is:

A

π×103 m\pi \times 10^3 \text{ m}

B

2×103 m2 \times 10^{-3} \text{ m}

C

2×103 m2 \times 10^3 \text{ m}

D

π×103 m\pi \times 10^{-3} \text{ m}

Step-by-Step Solution

The standard equation for the magnetic field of an electromagnetic wave travelling in the x-direction is given by: By=B0sin(kx+ωt)B_y = B_0 \sin(kx + \omega t) where kk is the propagation constant (or wave number) and ω\omega is the angular frequency.

1. Identify kk from the given equation: Comparing the given equation By=2×107sin(π×103x+3π×1011t)B_y = 2 \times 10^{-7} \sin(\pi \times 10^3x + 3\pi \times 10^{11}t) with the standard form, the coefficient of xx is kk: k=π×103 rad/mk = \pi \times 10^3 \text{ rad/m}

2. Calculate Wavelength (λ\lambda): The relationship between wavelength and propagation constant is: k=2πλk = \frac{2\pi}{\lambda} λ=2πk\lambda = \frac{2\pi}{k}

Substituting the value of kk: λ=2ππ×103\lambda = \frac{2\pi}{\pi \times 10^3} λ=2×103 m\lambda = 2 \times 10^{-3} \text{ m}

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut