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NEET PHYSICSEasy

Dimensions of magnetic field intensity is:

A

[M^{0}L^{-1}T^{0}A^{1}]

B

[MLT^{-1}A^{-1}]

C

[ML^{0}T^{-2}A^{-1}]

D

[MLT^{-2}A]

Step-by-Step Solution

To determine the dimensions of the magnetic field (BB), often referred to as magnetic field intensity in older contexts or competitive exams, we can use the Lorentz force formula: F=q(v×B)F = q(\mathbf{v} \times \mathbf{B}) . From this, the magnitude of the magnetic field is B=F/(qvsinθ)B = F / (qv \sin \theta). According to the sources, the dimensional formulae for the relevant quantities are:

  1. Force (FF): [MLT2][MLT^{-2}] .
  2. Charge (qq): [IT][IT] or [AT][AT] .
  3. Velocity (vv): [LT1][LT^{-1}] .

Substituting these dimensions into the formula for BB: [B]=[MLT2]/([AT]×[LT1])=[MLT2]/[LAT]=[MT2A1][B] = [MLT^{-2}] / ([AT] \times [LT^{-1}]) = [MLT^{-2}] / [LAT] = [MT^{-2}A^{-1}] .

This is represented as [ML0T2A1][ML^0T^{-2}A^{-1}], matching Option C. It is important to note that modern NCERT textbooks define 'Magnetic Intensity' (HH) as having dimensions [L1A][L^{-1}A] , but the context of the options confirms the question refers to the magnetic induction field (BB).

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