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NEET PHYSICSEasy

A wave traveling in the +ve x-direction having maximum displacement along y-direction as 1 m1 \text{ m}, wavelength 2π m2\pi \text{ m} and frequency of 1/π Hz1/\pi \text{ Hz}, is represented by:

A

y=sin(2πx2πt)y=\sin(2\pi x-2\pi t)

B

y=sin(10πx20πt)y=\sin(10\pi x-20\pi t)

C

y=sin(2πx+2πt)y=\sin(2\pi x+2\pi t)

D

y=sin(x2t)y=\sin(x-2t)

Step-by-Step Solution

Given: Amplitude (maximum displacement), A=1 mA = 1 \text{ m} Wavelength, λ=2π m\lambda = 2\pi \text{ m} Frequency, f=1π Hzf = \frac{1}{\pi} \text{ Hz}

The wave number kk is calculated as: k=2πλ=2π2π=1 m1k = \frac{2\pi}{\lambda} = \frac{2\pi}{2\pi} = 1 \text{ m}^{-1}

The angular frequency ω\omega is calculated as: ω=2πf=2π×1π=2 rad/s\omega = 2\pi f = 2\pi \times \frac{1}{\pi} = 2 \text{ rad/s}

The general equation for a wave traveling in the positive x-direction is given by: y=Asin(kxωt)y = A \sin(kx - \omega t)

Substituting the derived values into the equation: y=1sin(1x2t)=sin(x2t)y = 1 \sin(1x - 2t) = \sin(x - 2t)

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