Solved: PHYSICS Question for NEET | Sushrut

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NEET PHYSICSEasy

The distance between the two plates of a parallel plate capacitor is doubled, and the area of each plate is halved. If C is its initial capacitance, its final capacitance is equal to:

A

2C

B

C/2

C

4C

D

C/4

Step-by-Step Solution

Formula: The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$ , where $A$ is the area of the plates and $d$ is the separation distance.
Initial State: $C_{initial} = C = \frac{\varepsilon_0 A}{d}$ .
New Parameters:

New distance $d' = 2d$ .
New area $A' = \frac{A}{2}$ .

Final Capacitance: Substitute the new values into the formula: $C_{final} = \frac{\varepsilon_0 A'}{d'} = \frac{\varepsilon_0 (A/2)}{2d} = \frac{\varepsilon_0 A}{4d} = \frac{1}{4} \left( \frac{\varepsilon_0 A}{d} \right)$ .
Conclusion: $C_{final} = \frac{C}{4}$ .

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Solved: PHYSICS Question for NEET | Sushrut