Back to Directory
NEET PHYSICSMedium

A gas mixture consists of 2 moles of O2O_2 and 4 moles of Ar at temperature T. Neglecting all vibrational modes, the total internal energy of the system is:

A

4RT

B

15RT

C

9RT

D

11RT

Step-by-Step Solution

The total internal energy (UU) of a mixture of ideal gases is the sum of the internal energies of individual gases. The internal energy for nn moles of an ideal gas is given by U=f2nRTU = \frac{f}{2}nRT, where ff is the number of degrees of freedom.

  1. For Argon (Ar): It is a monatomic gas, so it has 3 degrees of freedom (f=3f=3) associated with translational motion . nAr=4n_{Ar} = 4 UAr=32(4)RT=6RTU_{Ar} = \frac{3}{2} (4) RT = 6RT

  2. For Oxygen (O2O_2): It is a diatomic gas. Neglecting vibrational modes, it has 5 degrees of freedom (f=5f=5; 3 translational + 2 rotational). nO2=2n_{O_2} = 2 UO2=52(2)RT=5RTU_{O_2} = \frac{5}{2} (2) RT = 5RT

Total Internal Energy: Utotal=UAr+UO2=6RT+5RT=11RTU_{total} = U_{Ar} + U_{O_2} = 6RT + 5RT = 11RT.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut