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NEET PHYSICSHard

Six similar bulbs are connected as shown in the figure with a DC source of emf E and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) in the situation when two from section A and one from section B are glowing, will be :

1

4 : 9

2

9 : 4

3

1 : 2

4

2 : 1

Step-by-Step Solution

(i) All bulbs are glowing: The equivalent resistance Req=R3+R3=2R3R_{eq} = \frac{R}{3} + \frac{R}{3} = \frac{2R}{3}. Power Pi=E2Req=3E22RP_i = \frac{E^2}{R_{eq}} = \frac{3E^2}{2R}. (ii) Two from section A and one from section B are glowing: The equivalent resistance Req=R2+R=3R2R_{eq} = \frac{R}{2} + R = \frac{3R}{2}. Power Pf=E2Req=2E23RP_f = \frac{E^2}{R_{eq}} = \frac{2E^2}{3R}. The ratio PiPf=3E22R×3R2E2=9:4\frac{P_i}{P_f} = \frac{3E^2}{2R} \times \frac{3R}{2E^2} = 9 : 4.

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