Since the circuit diagram is missing from the question text, we deduce its structure from the standard AIPMT 2010 problem. The circuit typically consists of an OR gate taking inputs A and B, whose output is fed into an AND gate along with the third input C. The Boolean expression for this circuit is $Y = (A + B) \cdot C$. To obtain an output $Y = 1$, the AND gate requires both of its inputs to be 1. Therefore, input $C$ must be 1, and the output of the OR gate $(A + B)$ must be 1 (which means either A or B or both must be 1). Let us check the given options: Option A: $Y = (0 + 1) \cdot 0 = 0$ Option B: $Y = (0 + 0) \cdot 1 = 0$ Option C: $Y = (1 + 0) \cdot 1 = 1 \cdot 1 = 1$ Option D: $Y = (1 + 0) \cdot 0 = 0$ Thus, the correct choice is A = 1, B = 0, C = 1.