Solved: PHYSICS Question for NEET

NEET PHYSICSMedium

A parallel plate capacitor has a uniform electric field $\vec{E}$ in the space between the plates. If the distance between the plates is ' $d$ ' and the area of each plate is ' $A$ ', the energy stored in the capacitor is ( $\varepsilon_0$ = permittivity of free space)

$\frac{1}{2} \varepsilon_0 E^2$

$\varepsilon_0 EAd$

$\frac{1}{2} \varepsilon_0 E^2 Ad$

$\frac{E^2 Ad}{\varepsilon_0}$

Step-by-Step Solution

Energy density associated with electric field is given by $u = \frac{dU}{dV} = \frac{1}{2} \varepsilon_0 E^2$ . Total energy stored $U = \int dU = \int \frac{1}{2} \varepsilon_0 E^2 dV = \frac{1}{2} \varepsilon_0 E^2 \int dV = \frac{1}{2} \varepsilon_0 E^2 V = \frac{1}{2} \varepsilon_0 E^2 Ad$ .

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