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NEET PHYSICSEasy

An electric dipole of moment p\vec{p} is lying along a uniform electric field E\vec{E}. The work done in rotating the dipole by 9090^{\circ} is:

A

2pE\sqrt{2}pE

B

pE2\frac{pE}{2}

C

2pE2pE

D

pEpE

Step-by-Step Solution

The work done by an external agent in rotating an electric dipole from an initial angle θ0\theta_0 to a final angle θ1\theta_1 in a uniform electric field is given by the change in potential energy: W=Uθ1Uθ0=pE(cosθ0cosθ1)W = U_{\theta_1} - U_{\theta_0} = pE(\cos\theta_0 - \cos\theta_1) [NCERT Class 12, Physics Part I, Sec 2.8.3, Eq 2.31].

  1. Initial Position: The dipole is lying along the electric field, which corresponds to the position of stable equilibrium. Thus, θ0=0\theta_0 = 0^{\circ}.
  2. Final Position: The dipole is rotated by 9090^{\circ}. Thus, θ1=90\theta_1 = 90^{\circ}.
  3. Calculation: W=pE(cos0cos90)W = pE(\cos 0^{\circ} - \cos 90^{\circ}) W=pE(10)W = pE(1 - 0) W=pEW = pE
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